document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49225>Question 49225</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2=|4+3x|  How do i solve problems like this? \r<BR>\n" );
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document.write( "|5x+1|<5   How do you isolate x when it is not an equation (<5 not =5)? Also, <BR>\n" );
document.write( "what needs to be manipulated to graph this on a horizontal graph? \r<BR>\n" );
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document.write( "3+|x-3|=7  How do I solve this algebraically?\r<BR>\n" );
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document.write( "Thankyou. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32650 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For absolute value problems, you will usually have two answers.  Since we don't know if the value of \"x\" is negative or positive, both cases must be considered.<BR>\n" );
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document.write( "2=|4+3x| <BR>\n" );
document.write( "Case # 1. [Just in case x = a positive number (x>0)]<BR>\n" );
document.write( "2=4+3x [For case #1, just drop the absolute value bars and solve for x]<BR>\n" );
document.write( "2-4=4-4+3x<BR>\n" );
document.write( "-2=+3x<BR>\n" );
document.write( "-2/3=+3x/3<BR>\n" );
document.write( "(-2/3) = x<BR>\n" );
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document.write( "Case #2 [Just in case x = a negative number (x<0)]<BR>\n" );
document.write( "2=|4+3x|<BR>\n" );
document.write( "(-1)(2) = 4+3x [Drop the absolute bars, mulitiply one of the sides by (-1)] <BR>\n" );
document.write( "-2 = 4+3x [Solve for x]<BR>\n" );
document.write( "-2-4=4-4+3x<BR>\n" );
document.write( "-6=3x<BR>\n" );
document.write( "-2=x<BR>\n" );
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document.write( "x = (-2/3) or x = -2<BR>\n" );
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document.write( "Check by pluggin the values of \"x\" back into the original equation.<BR>\n" );
document.write( "2=|4+3x|<BR>\n" );
document.write( "2=4+3(-2/3)<BR>\n" );
document.write( "2=4-2<BR>\n" );
document.write( "2=2 [Checks out]<BR>\n" );
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document.write( "2=|4+3x|<BR>\n" );
document.write( "-2=4+3(-2)<BR>\n" );
document.write( "-2=4-6<BR>\n" );
document.write( "-2=-2 [Also checks out, so both answers are correct]\r<BR>\n" );
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document.write( "|5x+1|<5 How do you isolate x when it is not an equation (<5 not =5)?<BR>\n" );
document.write( "Solve this the same as above, except when multiplying or dividing by a negative number, switch the inequality sign.<BR>\n" );
document.write( "|5x+1|<5 [Needs two cases in case x>0 or in case x<0]<BR>\n" );
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document.write( "Case #1. [Just in case x = a positive number (x>0)]<BR>\n" );
document.write( "|5x+1|<5<BR>\n" );
document.write( "5x+1<5 [Drop the absolute bars]<BR>\n" );
document.write( "5x+1-1<5-1  [Solve for x]<BR>\n" );
document.write( "5x<4<BR>\n" );
document.write( "5x/5<4/5<BR>\n" );
document.write( "x<4/5<BR>\n" );
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document.write( "Case #2.[Just in case x = a negative number (x<0)]\r<BR>\n" );
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document.write( "|5x+1|<5 <BR>\n" );
document.write( "5x+1<5  [Drop the absolute bars[<BR>\n" );
document.write( "5x+1>(-1)5 [Multiply one side by (-1)and immediately switch the inequality sign]<BR>\n" );
document.write( "5x+1>-5  [Solve for x]<BR>\n" );
document.write( "5x+1-1>-5-1<BR>\n" );
document.write( "5x>-6<BR>\n" );
document.write( "5x/5>-6/5<BR>\n" );
document.write( "x>-6/5<BR>\n" );
document.write( "-6/5 or -1.2<BR>\n" );
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document.write( "x<4/5 AND x>-6/5 [Final answer]<BR>\n" );
document.write( "[If the inequality is \"less thAND\" the graph will be \"and\".  If the inequality is greatOR, the graph will be an \"or\".]<BR>\n" );
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document.write( "Also, what needs to be manipulated to graph this on a horizontal graph? <BR>\n" );
document.write( "To graph you know that the two points will overlap because it is an AND graph (less thAND).  Every point from -6/5 through 4/5 is included in the graph.\r<BR>\n" );
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document.write( "<______-2______(-1.2=======-1======0=====4/5) ___1______2_____><BR>\n" );
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document.write( "The interval notation includes every point between (-1.2, 4.5)\r<BR>\n" );
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document.write( "3+|x-3|=7 How do I solve this algebraically? <BR>\n" );
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document.write( "Case #1.[Just in case x = a positive number (x>0)]\r<BR>\n" );
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document.write( "3+|x-3|=7 <BR>\n" );
document.write( "3+x-3=7 [Drop the absolute bars]<BR>\n" );
document.write( "x=7 [Solve for x]\r<BR>\n" );
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document.write( "Case #2 [Just in case x = a negative number (x<0)]<BR>\n" );
document.write( "3+|x-3|=7<BR>\n" );
document.write( "3+x-3=7 [Drop the absolute bars]<BR>\n" );
document.write( "3+x-3=(-1)(7) [Multiply one side by (-1)]<BR>\n" );
document.write( "3+x-3=-7 [Solve for x]<BR>\n" );
document.write( "x=-7<BR>\n" );
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document.write( "x = 7 or x = -7\r<BR>\n" );
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document.write( " </SPAN>\n" );
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