document.write( "Question 476093: Dear math teacher, \r
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document.write( "I am having difficulties with the following problem:
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document.write( "(a)Find n; (b) n cannot equal to .... integers.
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document.write( "(n+2)Cn = 45
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document.write( "(n+2)(n+1)n!/(2.1)n! = 45 and after canceling n! we get
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document.write( "(n+2)(n+1) = 90
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document.write( "n^2 + 3n - 88 = 0
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document.write( "(n+11)(n-8) = 0
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document.write( "n = -11 and n = 8\r
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document.write( "My answer for (a) is n = 8 only since factorial is not defined for negative numbers. For (b), our n cannot equal -11 and zero since n was canceled out above. Please let me know if my reasoning is correct. \r
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document.write( "Thank you very much. \r
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document.write( "I. \n" );
document.write( "
Algebra.Com's Answer #326486 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! You are correct. Good job. You can verify this by plugging in n=8 and evaluating (n+2) C n to get\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(n+2) C n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(8+2) C 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10 C 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(10!)/(8!(10-8)!)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(10*9*8!)/(8!2!)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(10*9)/(2*1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "90/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "45\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So this verifies the answer. \n" ); document.write( " |