document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=476083>Question 476083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 20 copper should be mixed with 600 ounces of an alloy that is 70% copper in order to get an alloy that is 30% copper </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #326481 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=326481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 20% copper should be mixed with 600 ounces of an alloy that is 70% copper in order to get an alloy that is 30% copper<BR>\n" );
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document.write( "Let x = amt of 20% copper required to accomplish this<BR>\n" );
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document.write( ".20x + .70(600) = .30(x+600)<BR>\n" );
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document.write( ".20x + 420 = .30x + 180<BR>\n" );
document.write( ".20x - .30x = 180 - 420<BR>\n" );
document.write( "-.10x = -240<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-240%29%2F%28-.10%29 ALIGN=MIDDLE  ALT=\"%28-240%29%2F%28-.10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 2400 oz of 20% copper required </SPAN>\n" );
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