document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=476036>Question 476036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! In this question, there is a circle inscribed in a square with a width of 4cm. Find the radius of a circle tangent to the circle and two edges of the square.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #326456 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=326456\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2 the diagonal, from the center to the corner, is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2sqrt%282%29 ALIGN=MIDDLE  ALT=\"2sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > cm<BR>\n" );
document.write( "From the center to the circle is 2 cm<BR>\n" );
document.write( "The diameter of the small circle = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2sqrt%282%29+-+2 ALIGN=MIDDLE  ALT=\"2sqrt%282%29+-+2\"   DISABLED_style= \"max-width:90%; height:auto;\" > cm<BR>\n" );
document.write( "Its radius = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282%29+-+1 ALIGN=MIDDLE  ALT=\"sqrt%282%29+-+1\"   DISABLED_style= \"max-width:90%; height:auto;\" > cm<BR>\n" );
document.write( "=~ 0.414 cm<BR>\n" );
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document.write( "*************** That's not right, I'm working on it.<BR>\n" );
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