document.write( "Question 475995: Can you show me how to solve the following? It says write an equation of the line that goes through the point (-8,7) and is perpendicular to the line -4x+3y=11. \n" ); document.write( "
Algebra.Com's Answer #326447 by Tatiana_Stebko(1539)\"\" \"About 
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Find the slope of the given line \"4x%2B3y=11\"
\n" ); document.write( "\"3y=-4x%2B11\"
\n" ); document.write( "\"y=%28-4%2F3%29x%2B11%2F3\", the slope is \"m1=%28-4%2F3%29\"
\n" ); document.write( "Perpendicular lines are lines whose slopes are negative reciprocals of one another, \"m1%2Am2=-1\"
\n" ); document.write( "then the slope of the line that we have to find \"m2=-1%2F%28m1%29\"
\n" ); document.write( "\"m2=-1%2F%28-4%2F3%29=3%2F4\"
\n" ); document.write( "The point-slope form of a line uses a point (x1,y1) and a slope (m), to write the equation of a line. This form is given by the equation:
\n" ); document.write( "\"y+-+y1=+m%28x+-+x1%29\"
\n" ); document.write( "Point (-8,7) substitue into formula \"x1=-8\", \"y1=7\"; \"m=3%2F4+\"
\n" ); document.write( "\"y-7=%283%2F4%29%28x-%28-8%29%29\" multiply by 4
\n" ); document.write( "\"4y-28=3x%2B24\"
\n" ); document.write( "\"3x-4y=-52\"\r
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