document.write( "Question 475892: log 16 32 = x +2 find the solution and explain the steps \n" ); document.write( "

Algebra.Com's Answer #326411 by lwsshak3(11628) $\"\"$ $\"About$

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log 16 32 = x +2 find the solution and explain the steps
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\n" ); document.write( "log16(32)=x+2
\n" ); document.write( "convert to exponential form: (base(16) raised to log of number(x+2)=number(32)
\n" ); document.write( "16^(x+2)=32
\n" ); document.write( "(16=2^4)
\n" ); document.write( "(2^4)^(x+2)=32
\n" ); document.write( "2^4(x+2)=32
\n" ); document.write( "(32=2^5)
\n" ); document.write( "2^(4x+8)=2^5
\n" ); document.write( "equate exponents with same base 2
\n" ); document.write( "4x+8=5
\n" ); document.write( "4x=-3
\n" ); document.write( "x=-3/4
\n" ); document.write( "Check:
\n" ); document.write( "16^(x+2)=16^(-3/4+2)=16^(5/4)=32 \n" ); document.write( "

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