document.write( "Question 475364: let m and n be two consicutive even integers and 1/m+1/n=p/q (in the lowest form) prove that (p, q, q+1) is a pythagorous triplet. \n" ); document.write( "
Algebra.Com's Answer #326405 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
Instead of writing n we can write m+2, in which\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "And we want to prove that \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Begin by letting m = 2k, so our equation becomes\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Simplify the LHS by dividing both top and bottom by 2:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The denominator is equal to 2k(k+1), in which k+1, 2k, 2k+1 are all pairwise relatively prime. Hence, the LHS is irreducible, so we can say that\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "And that , so we are done.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );