document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=475903>Question 475903</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From 6 chemists and 5 biologists, a committee of 7 is to be chosen so as to include 4 chemists. In how many ways can this be done? \r<BR>\n" );
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document.write( "Here is how I did it: \r<BR>\n" );
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document.write( "11C4 times 7C3 = 8250 but it is the wrong answer. Where did I went wrong? Please help me figure this one out. Thank you very much. \r<BR>\n" );
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document.write( "I. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #326340 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=326340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1 committee=4 chemists, 3 biologists=<BR>\n" );
document.write( "6C4 X 5C3=(6x5x4x3x2!/4x3x2x2!) X (5x4x3x2!/3x2x2!)=<BR>\n" );
document.write( "(5x3) X (5x2)=15 X 10=150..<BR>\n" );
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