document.write( "Question 474848: i need help solving this and the steps logx-1=-log(x-9) and also
\n" ); document.write( "log(1-x)+logx+log(x+4) \n" ); document.write( "
Algebra.Com's Answer #326321 by lwsshak3(11628)\"\" \"About 
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i need help solving this and the steps logx-1=-log(x-9) and also
\n" ); document.write( "log(1-x)+logx+log(x+4)
\n" ); document.write( "**
\n" ); document.write( "logx-1=-log(x-9)
\n" ); document.write( "logx-1+log(x-9)=1
\n" ); document.write( "logx+log(x-9)=1
\n" ); document.write( "log(x)(x-9)=1
\n" ); document.write( "convert to exponential form: (base(10) raised to log of number(1)=number(x(x+9))
\n" ); document.write( "10^1=(x)(x-9)=10
\n" ); document.write( "x^2-9x-10=0
\n" ); document.write( "(x-10)(x+1)=0
\n" ); document.write( "x=10
\n" ); document.write( "or
\n" ); document.write( "x=-1 (reject, x-9>0)
\n" ); document.write( "..
\n" ); document.write( "log(1-x)+logx+log(x+4)
\n" ); document.write( "log(1-x)(x)(x+4)
\n" ); document.write( "We need an equation to come up with a solution \n" ); document.write( "
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