document.write( "Question 475804: the sum of two numbers is 41, the larger number is 1 less than twice the smaller number: translate the word problem into a system of two linear equations. \r
\n" ); document.write( "\n" ); document.write( "After you have the two equations then show work to solve.\r
\n" ); document.write( "\n" ); document.write( "This is a discussion post question. THank you for your help! \n" ); document.write( "
Algebra.Com's Answer #326316 by ankor@dixie-net.com(22740)\"\" \"About 
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the sum of two numbers is 41, the larger number is 1 less than twice the smaller number:
\n" ); document.write( " translate the word problem into a system of two linear equations.
\n" ); document.write( ":
\n" ); document.write( "Let x = one number which is the larger
\n" ); document.write( "let y = another number
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"the sum of two numbers is 41,\"
\n" ); document.write( "x + y = 41
\n" ); document.write( ":
\n" ); document.write( "\" the larger number is 1 less than twice the smaller number:\"
\n" ); document.write( "x = 2y - 1
\n" ); document.write( ":
\n" ); document.write( "To solve it, we can substitute (2y-1) for x in the 1st equation;
\n" ); document.write( "(2y-1) + y = 41
\n" ); document.write( "2y + y - 1 = 41
\n" ); document.write( "3y = 41 + 1
\n" ); document.write( "3y = 42
\n" ); document.write( "y = \"42%2F3\"
\n" ); document.write( "y = 14
\n" ); document.write( ":
\n" ); document.write( "Use the 2nd equation to find x
\n" ); document.write( ":
\n" ); document.write( "x = 2y - 1
\n" ); document.write( "x = 2(14) - 1
\n" ); document.write( "x = 27
\n" ); document.write( ":
\n" ); document.write( "Check solutions in the 1st equation \n" ); document.write( "
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