document.write( "Question 49107: In a certain class, 1/3 of the girls are 1/5 if tge students. What is the ratio of boys to girls in the class?\r
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\n" ); document.write( "\n" ); document.write( "I know that they have more boys, can you help.\r
\n" ); document.write( "\n" ); document.write( "Thanks! \n" ); document.write( "

Algebra.Com's Answer #32627 by Born2TeachMath(20) $\"\"$ $\"About$

You can put this solution on YOUR website!
Actually, you're wrong! There are more girls than boys, but it doesn't sound like it, does it?
\n" ); document.write( "You can play around with variables, and \"let g = # of girls\", etc. but that's not the way to do this.
\n" ); document.write( "It says that 1/3 of the girls are 1/5 of the students. That means that the next 1/3 of the girls is another 1/5 of the students, and the last 1/3 of the girls are yet another 1/5 of the students. Therefore, if you combine all three 1/3's of the girls, that must be all of the girls. This also accounts for 1/5 + 1/5 + 1/5 = 3/5 of the students. So the girls are 3/5 of the students, which means the boys must be the other 2/5 of the students. So to find a ratio, express it as a fraction of boys on top with fraction of girls on bottom. This becomes $\"%282%2F5%29%2F%283%2F5%29\"$ . Now, if you remember how to divide fractions, you flip the bottom fraction over, and then multiply the two together: $\"%282%2F5%29+%2A+%285%2F3%29\"$ . Remember, when multiplying fractions, don't actually multiply the numbers out - just cancel the 5 on the top with the 5 on the bottom, and the fraction becomes $\"%282%2F3%29\"$ . Since we put the boys on the top, the answer to your problem is 2 to 3 for boys to girls.
\n" ); document.write( "Look, more girls than boys!! \n" ); document.write( "

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