document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49205>Question 49205</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could someone help me with this please. Word problems. Geometry\r<BR>\n" );
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document.write( "Geometry: The length of a rectangle is 1 cm longer than it's width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32623 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32623\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length of the rectangle be L and its width be W.<BR>\n" );
document.write( "The length, L, is 1 cm longer than the width, W, so L = W+1<BR>\n" );
document.write( "The sides of the rectangle can be written in terms of the width: L=(W+1) and W=(W).<BR>\n" );
document.write( "The diagonal of the rectangle forms the hypotenuse (c) of a right triangle whose sides are (W+1) and (W).\r<BR>\n" );
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document.write( "Using the Pythagorean theorem: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2+=+a%5E2%2Bb%5E2 ALIGN=MIDDLE  ALT=\"c%5E2+=+a%5E2%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, you can find W:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%5E2+=+%28W%2B1%29%5E2+%2B+W%5E2 ALIGN=MIDDLE  ALT=\"4%5E2+=+%28W%2B1%29%5E2+%2B+W%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16+=+W%5E2%2B2W%2B1+%2B+W%5E2 ALIGN=MIDDLE  ALT=\"16+=+W%5E2%2B2W%2B1+%2B+W%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Collect like-terms.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2W%5E2%2B2W%2B1+=+16 ALIGN=MIDDLE  ALT=\"2W%5E2%2B2W%2B1+=+16\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 16 from both sides of the equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2W%5E2%2B2W-15+=+0 ALIGN=MIDDLE  ALT=\"2W%5E2%2B2W-15+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Use the quadratic formula to solve: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a ALIGN=MIDDLE  ALT=\"W=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+%28-2%2B-sqrt%282%5E2-4%282%29%28-15%29%29%29%2F2%282%29 ALIGN=MIDDLE  ALT=\"W+=+%28-2%2B-sqrt%282%5E2-4%282%29%28-15%29%29%29%2F2%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+%28-2%2B-sqrt%284%2B120%29%29%2F4 ALIGN=MIDDLE  ALT=\"W+=+%28-2%2B-sqrt%284%2B120%29%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+%28-2%2B-sqrt%28124%29%29%2F4 ALIGN=MIDDLE  ALT=\"W+=+%28-2%2B-sqrt%28124%29%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+%28-2%2B-2sqrt%2831%29%29%2F4 ALIGN=MIDDLE  ALT=\"W+=+%28-2%2B-2sqrt%2831%29%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+-1%2F2-%281%2F2%29sqrt%2831%29 ALIGN=MIDDLE  ALT=\"W+=+-1%2F2-%281%2F2%29sqrt%2831%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Discard this solution as the width must be a positive number.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+-1%2F2+%2B+%281%2F2%29sqrt%2831%29 ALIGN=MIDDLE  ALT=\"W+=+-1%2F2+%2B+%281%2F2%29sqrt%2831%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "For an approximate answer:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+-1%2F2%2B%281%2F2%29%285.57%29 ALIGN=MIDDLE  ALT=\"W+=+-1%2F2%2B%281%2F2%29%285.57%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+2.28 ALIGN=MIDDLE  ALT=\"W+=+2.28\"   DISABLED_style= \"max-width:90%; height:auto;\" >cm<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L+=+W%2B1 ALIGN=MIDDLE  ALT=\"L+=+W%2B1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L+=+3.28 ALIGN=MIDDLE  ALT=\"L+=+3.28\"   DISABLED_style= \"max-width:90%; height:auto;\" >cm </SPAN>\n" );
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