document.write( "Question 475727: What are the zeros if P(x) and their multiplicities: P(x)=(x+5)^3(x-6)(-x+6)
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Algebra.Com's Answer #326220 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"P%28x%29=%28x%2B5%29%5E3%28x-6%29%28-x%2B6%29\"....set \"P%28x%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%5E3%28x-6%29%28-x%2B6%29=0\"...the product is equal to zero if any of multiplicands is equal to zero\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%5E3=0\"...->....\"%28x%2B5%29=0\"...->....\"x=-5\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-6%29=0\"...->....\"%28x-6%29=0\"...->....\"x=6\"\r
\n" ); document.write( "\n" ); document.write( "\"%28-x%2B6%29=0\"...->....\"6=x\"...or....\"x=6\"\r
\n" ); document.write( "\n" ); document.write( "so, zeros are:\"x=-5\" and \"x=6\"
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