document.write( "Question 475655: The tens digit is 5 more than the unit digit. If the sum of their squares is 53, find the number. \n" ); document.write( "

Algebra.Com's Answer #326211 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "The tens digit is 5 more than the unit digit
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document.write( "let x and (x+5) represent the unit's and ten's digits respectively
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document.write( "Question states***
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document.write( " x^2 + (x+5)^2 = 53
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document.write( " 2x^2 + 10x - 28 = 0
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document.write( " x^2 + 5x - 14 = 0 
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document.write( "factoring
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document.write( "(x+7)(x-2) = 0
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document.write( "(x+7)= 0  x = -7  tossing out negative number for a digit amount
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document.write( "(x-2) = 0 x = 2, one's digit, ten digit is 7.  Number is 72.\r
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document.write( "CHECKING our Answer***
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document.write( " 2^2 + 7^2 = 4 + 49 = 53 \n" );
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