document.write( "Question 475652: Judy wants to invest $50,000. Part of it is invested in a fund that pays 12.5% and the remainder in one that pays 14%. Find the amount invested at each rate if the annual income from the two is $6,640. \n" ); document.write( "
Algebra.Com's Answer #326186 by mananth(16946)\"\" \"About 
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Investment I 12.50% per annum
\n" ); document.write( "Investment II 14.00% per annum
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\n" ); document.write( "x + y 50000 ------------------------1
\n" ); document.write( "12.50% x + 14.00% y = $6,640.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "12.5 x + 14 y = $664,000.00 --------2
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\n" ); document.write( "Multiply (1) by -12.5
\n" ); document.write( "we get
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\n" ); document.write( "-12.5 x -12.5 y = -625000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "0 x 1.5 y = $39,000.00
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\n" ); document.write( "divide by 1.5
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\n" ); document.write( "y= $26,000.00 investment at 14.00%
\n" ); document.write( "Balance $24,000.00 investment at 12.50%\r
\n" ); document.write( "\n" ); document.write( "CHECK
\n" ); document.write( "$24,000.00------- $3,000.00
\n" ); document.write( "$26,000.00------- $3,640.00
\n" ); document.write( "Total $6,640.00\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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