document.write( "Question 475553: Money and Mixture Problems: \r
\n" ); document.write( "\n" ); document.write( "Jerry invested $7000, part at 8% simple interest and the rest at 5% simple interest for a period of 1 year. If he received a total annual interest of $476 from both investments, how much did he invest at each rate?
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Algebra.Com's Answer #326147 by mananth(16946) $\"\"$ $\"About$

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Investment I 8.00% per annum
\n" ); document.write( "Investment II 5.00% per annum
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\n" ); document.write( "x+y 7000 ------------------------1
\n" ); document.write( "8.00%x+5.00%y=$476.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "8x+5y= $47,600.00 --------2
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\n" ); document.write( "Multiply (1) by -8
\n" ); document.write( "we get
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\n" ); document.write( "-8x-8y= -56000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "-3y=-$8,400.00
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\n" ); document.write( "divide by-3
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\n" ); document.write( "y=$2,800.00----investment at 5.00%
\n" ); document.write( "Balance $4,200.00----investment at 8.00%
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "

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