document.write( "Question 475602: A man invested $2000, part at 8% and part at 6%. He earned $144
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Algebra.Com's Answer #326129 by mananth(16946)\"\" \"About 
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Investment I 8.00% per annum
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\n" ); document.write( "x+y=2000 ------------------------1
\n" ); document.write( "8.00% x + 6.00% y = $144.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "8x+6y= $14,400.00 --------2
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\n" ); document.write( "Multiply (1) by -8
\n" ); document.write( "we get
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\n" ); document.write( "-8x-8y= -16000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "-2y=-$1,600.00
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\n" ); document.write( "divide by -2
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\n" ); document.write( "y=$800.00 investment at 6.00%
\n" ); document.write( "Balance $1,200.00 investment at 8.00%\r
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