document.write( "Question 475602: A man invested $2000, part at 8% and part at 6%. He earned $144
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document.write( "from his investments. How much did he invest at 8% \n" );
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Algebra.Com's Answer #326129 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Investment I 8.00% per annum \n" ); document.write( "Investment II 6.00% per annum \n" ); document.write( " \n" ); document.write( "x+y=2000 ------------------------1 \n" ); document.write( "8.00% x + 6.00% y = $144.00 \n" ); document.write( "Multiply by 100 \n" ); document.write( "8x+6y= $14,400.00 --------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -8 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-8x-8y= -16000.00 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "-2y=-$1,600.00 \n" ); document.write( " \n" ); document.write( "divide by -2 \n" ); document.write( " \n" ); document.write( "y=$800.00 investment at 6.00% \n" ); document.write( "Balance $1,200.00 investment at 8.00%\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.com \n" ); document.write( " |