document.write( "Question 475596: Factor the polynomial completely\r
\n" ); document.write( "\n" ); document.write( "3x^3-6x^2-5x+10 \n" ); document.write( "
Algebra.Com's Answer #326124 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"3x%5E3-6x%5E2-5x%2B10\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%5E3-6x%5E2%29%2B%28-5x%2B10%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%28x-2%29-5%28x-2%29\" Factor out the GCF \"3x%5E2\" out of the first group. Factor out the GCF \"-5\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%5E2-5%29%28x-2%29\" Since we have the common term \"x-2\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"3x%5E3-6x%5E2-5x%2B10\" factors to \"%283x%5E2-5%29%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"3x%5E3-6x%5E2-5x%2B10=%283x%5E2-5%29%28x-2%29\"
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