document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=472177>Question 472177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3/2<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+log%28+27+%29+ ALIGN=MIDDLE  ALT=\"+log%28+27+%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >(x+5)=1\r<BR>\n" );
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document.write( "Help is needed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #326110 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=326110\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/2log27(x+5)=1<BR>\n" );
document.write( "log27(x+5)=2/3<BR>\n" );
document.write( "convert to exponential form: (base(27) raised to log of number(2/3)=number(x+5)<BR>\n" );
document.write( "27^2/3=x+5<BR>\n" );
document.write( "9=x+5<BR>\n" );
document.write( "x=9-5=4<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "3/2log27(x+5)<BR>\n" );
document.write( "3/2log27(4+5)<BR>\n" );
document.write( "3/2log27(9)<BR>\n" );
document.write( "3/2*2/3=1 </SPAN>\n" );
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