document.write( "Question 472548: 1+(4/3)\"+log%28x-3%2C+4+%29+\" =11/3 \r
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Algebra.Com's Answer #326106 by lwsshak3(11628)\"\" \"About 
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1+(4/3)log(x-3) (4) =11/3
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\n" ); document.write( "(4/3)log(x-3) (4) =11/3-1=11/3-3/3=8/3
\n" ); document.write( "log(x-3) (4)=24/12=2
\n" ); document.write( "convert to exponential form: (base(x-3) raised to log of number (2)=number=4)
\n" ); document.write( "(x-3)^2=4
\n" ); document.write( "x-3=±√4=±2
\n" ); document.write( "x=3+2=5
\n" ); document.write( "or
\n" ); document.write( "x=3-2=1 (reject, (x-3)>1)
\n" ); document.write( "ans:
\n" ); document.write( "x=5
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