document.write( "Question 472548: 1+(4/3) =11/3 \r
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document.write( "Solve for x. Please I need help. \n" );
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Algebra.Com's Answer #326106 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! 1+(4/3)log(x-3) (4) =11/3 \n" ); document.write( "Solve for x. Please I need help. \n" ); document.write( "** \n" ); document.write( "(4/3)log(x-3) (4) =11/3-1=11/3-3/3=8/3 \n" ); document.write( "log(x-3) (4)=24/12=2 \n" ); document.write( "convert to exponential form: (base(x-3) raised to log of number (2)=number=4) \n" ); document.write( "(x-3)^2=4 \n" ); document.write( "x-3=±√4=±2 \n" ); document.write( "x=3+2=5 \n" ); document.write( "or \n" ); document.write( "x=3-2=1 (reject, (x-3)>1) \n" ); document.write( "ans: \n" ); document.write( "x=5 \n" ); document.write( " |