document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=475537>Question 475537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Set up an equation that can be used to solve the problem. Solve the equation and answer the question asked:\r<BR>\n" );
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document.write( "One number is 5 less than 3 times a second number. Their sum is 43. Find the numbers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #326095 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=326095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is 5 less than 3 times a second number. <BR>\n" );
document.write( "Their sum is 43. Find the numbers.<BR>\n" );
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document.write( "x = 3y -5<BR>\n" );
document.write( "x + y = 43<BR>\n" );
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document.write( "Substitute for \"x\" and solve for \"y\":<BR>\n" );
document.write( "3y-5 + y = 43<BR>\n" );
document.write( "4y = 38<BR>\n" );
document.write( "y = 19/2 = 9.5<BR>\n" );
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document.write( "Solve for \"x\":<BR>\n" );
document.write( "x = 3(9.5) - 5<BR>\n" );
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document.write( "x = 28.5 - 5<BR>\n" );
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document.write( "x = 23.5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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