document.write( "Question 475054: erica took 6 hours in all to hike up the 12 mile mountain trail and back down. Her rate coming down was twice as fast as her rate going up. What was her rate going up the mountain? \n" ); document.write( "

Algebra.Com's Answer #326075 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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6 hours to hike up the 12 mile mountain trail and back down.
\n" ); document.write( "rate coming down was twice as fast as rate going up.
\n" ); document.write( " What was the rate going up the mountain?
\n" ); document.write( ":
\n" ); document.write( "r = going up rate
\n" ); document.write( "then
\n" ); document.write( "2r = rate coming down
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/rate
\n" ); document.write( ":
\n" ); document.write( "Up time + down time = 6 hr
\n" ); document.write( " $\"12%2Fr\"$ + $\"12%2F%282r%29\"$ = 6
\n" ); document.write( "mult eq by 2r, results
\n" ); document.write( "2(12) + 12 = 2r(6)
\n" ); document.write( "24 + 12 = 12r
\n" ); document.write( "36 = 12r
\n" ); document.write( "r = $\"36%2F12\"$
\n" ); document.write( "r = 3 mph rate going up
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the actual times
\n" ); document.write( "12/3 = 4 hrs
\n" ); document.write( "12/6 = 2 hrs
\n" ); document.write( "-----------
\n" ); document.write( "total: 6 hrs \n" ); document.write( "

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