document.write( "Question 475518: find the
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\n" ); document.write( "maximum or minimum value of f(x)
\n" ); document.write( "graph the function\r
\n" ); document.write( "\n" ); document.write( "f(x)=1/5(x+4)^2+3\r
\n" ); document.write( "\n" ); document.write( "^means raising to that power and 1/5 is a fraction
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Algebra.Com's Answer #326073 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "Using the vertex form of a parabola, \"y=a%28x-h%29%5E2+%2Bk\" where(h,k) is the vertex
\n" ); document.write( "f(x)=1/5(x+4)^2+3
\n" ); document.write( "Vertex is (-4,3) Line of symmetry is x = -4
\n" ); document.write( " a = 1/5, a>0 Parabola opens upward, Vertex is a minimum Pt. f(x) = 3
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