document.write( "Question 475339: Line/ goes through the point (5,2) and is perpendicular to the line through(-2,1) and (-4,-2). Find the equation (in slope form) for/. \n" ); document.write( "
Algebra.Com's Answer #325982 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
slope of line passing through (-2,1) & (-4,-2) \r
\n" ); document.write( "\n" ); document.write( "x1 y1 x2 y2
\n" ); document.write( "-2 1 -4 -2
\n" ); document.write( "
\n" ); document.write( "slope m = (y2-y1)/(x2-x1)
\n" ); document.write( "( -2 - 1 )/( -4 - -2 )
\n" ); document.write( "( -3 / -2 )
\n" ); document.write( "m= 1.50 OR 3/2
\n" ); document.write( "The line perpendicular to this line will have a slope of -2/3\r
\n" ); document.write( "\n" ); document.write( "Equation of line with slope -2/3 and passing through (5,2)
\n" ); document.write( "Find the intercept b\r
\n" ); document.write( "\n" ); document.write( "Plug value of the slope -2/3 and point (5,2) in
\n" ); document.write( "Y = m x + b
\n" ); document.write( "2.00 = -3.75 + b
\n" ); document.write( "b= 2 +3.75
\n" ); document.write( "b= 5.75
\n" ); document.write( "So the equation will be
\n" ); document.write( "Y = -0.75 x + 5.75
\n" ); document.write( "m.ananth@hotmail.ca \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );