document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15532>Question 15532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I submitted this problem Friday evening and I got no response. I need to know if I'm right or wrong, it's due tomorrow.<BR>\n" );
document.write( "If 10 cards are drawn without replacement from an ordinary deck, find the probability of obtaining exactly 3 aces or exactly 3 kings (or both). I tried<BR>\n" );
document.write( "using (52 choose 10) for the denominator and (10 choose 3)^4 for the numerator(4 for each suite). It seems as though I'm missing something. Please help asap.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325981 by </B><A HREF=/tutors/aboutme.mpl?userid=biplavmehta><B>biplavmehta(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=biplavmehta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> total no. of cases= 52c10<BR>\n" );
document.write( "if 3ace are selected favorable no. of cases= 4c3*48c7<BR>\n" );
document.write( "if 3kings are selected favorable no. of cases= 4c3*48c7<BR>\n" );
document.write( "if 3ace and 3kings selected favorable no. of cases= 4c3*4c3*46c4\r<BR>\n" );
document.write( "\n" );
document.write( "final result= (4c3*48c7 + 4c3*48c7 + 4c3*4c3*46c4) / 52c10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );