document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15704>Question 15704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi,\r<BR>\n" );
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document.write( "I'm trying to solve this  problem: If a 3-digit number (000 to 999) is chosen at random, find the probability that exactly one digit will be less than 2.<BR>\n" );
document.write( "I got to the point of (1/10)^2 * 2/10 but I'm not sure or am I answering another problem. Please help asap.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325974 by </B><A HREF=/tutors/aboutme.mpl?userid=biplavmehta><B>biplavmehta(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=biplavmehta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let 1st digit is less then 2 and remaining more then equal to 2. then we have 2*8*8 favorable no. of cases.<BR>\n" );
document.write( "similarly for 2nd and 3rd digit.<BR>\n" );
document.write( "so the total no. of favorable cases = 2*8*8 + 8*2*8 + 8*8*2 = 384.<BR>\n" );
document.write( "total no. of cases= 10*10*10=1000<BR>\n" );
document.write( "ans= 384/1000.  </SPAN>\n" );
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