document.write( "Question 475317: THE SUM OF THE DIGITS OF THE TWO DIGITS- NUMBER IS 12.If the order of the digits is reversed,the resulting number is 18 more than the original number.FIND THE ORIGINAL NUMBER.
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Algebra.Com's Answer #325938 by ccs2011(207)\"\" \"About 
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Let the 2-digit number be AB, where A is in the ten's place and B is in the one's place.
\n" ); document.write( "The value of AB is 10*A + B
\n" ); document.write( "If you reverse the order to BA then the value is 10*B + A
\n" ); document.write( "Set up equations:
\n" ); document.write( "We know the sum of A and B is 12. We know the value of BA is 18 more than value of AB.
\n" ); document.write( "\"A+%2B+B+=+12\"
\n" ); document.write( "\"10B+%2B+A+=+10A+%2B+B+%2B+18\"
\n" ); document.write( "Combine like terms in 2nd equation
\n" ); document.write( "Subtract B on both sides, Subtract A on both sides
\n" ); document.write( "\"9B+=+9A+%2B+18\"
\n" ); document.write( "Divide by 9 on both sides
\n" ); document.write( "\"B+=+A+%2B+2\"
\n" ); document.write( "Now substitute A+2 for B in 1st equation:
\n" ); document.write( "\"A+%2B+%28A%2B2%29+=+12\"
\n" ); document.write( "\"2A+%2B+2+=+12\"
\n" ); document.write( "Subtract 2 on both sides
\n" ); document.write( "\"2A+=+10\"
\n" ); document.write( "Divide by 2 on both sides
\n" ); document.write( "\"A+=+5\"
\n" ); document.write( "B = A + 2 = 5+2 = 7
\n" ); document.write( "Therefore the original number (AB) is 57
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