document.write( "Question 475317: THE SUM OF THE DIGITS OF THE TWO DIGITS- NUMBER IS 12.If the order of the digits is reversed,the resulting number is 18 more than the original number.FIND THE ORIGINAL NUMBER.
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Algebra.Com's Answer #325938 by ccs2011(207)![]() ![]() You can put this solution on YOUR website! Let the 2-digit number be AB, where A is in the ten's place and B is in the one's place. \n" ); document.write( "The value of AB is 10*A + B \n" ); document.write( "If you reverse the order to BA then the value is 10*B + A \n" ); document.write( "Set up equations: \n" ); document.write( "We know the sum of A and B is 12. We know the value of BA is 18 more than value of AB. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Combine like terms in 2nd equation \n" ); document.write( "Subtract B on both sides, Subtract A on both sides \n" ); document.write( " \n" ); document.write( "Divide by 9 on both sides \n" ); document.write( " \n" ); document.write( "Now substitute A+2 for B in 1st equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Subtract 2 on both sides \n" ); document.write( " \n" ); document.write( "Divide by 2 on both sides \n" ); document.write( " \n" ); document.write( "B = A + 2 = 5+2 = 7 \n" ); document.write( "Therefore the original number (AB) is 57 \n" ); document.write( " |