![\"\"](\"/images/stars/stars-13.gif\")
You can put this solution on YOUR website!
find the focus 1/4(x-2)^2=(y+3)
\n" ); document.write( "and find the vertex and Directrix of -1/8(y+3)^2=(x-1)
\n" ); document.write( "**
\n" ); document.write( "focus:
\n" ); document.write( "1/4(x-2)^2=(y+3)
\n" ); document.write( "(x-2)^2=4(y+3)
\n" ); document.write( "This is a parabola with axis of symmetry: x=2 of the standard form: (x-h)^2=4p(y-k), with (h,k) being the (x,y) coordinates of the vertex. Parabola opens upwards.
\n" ); document.write( "For given equation:(x-2)^2=4(y+3)
\n" ); document.write( "vertex: (2,-3)
\n" ); document.write( "4p=4
\n" ); document.write( "p=1
\n" ); document.write( "focus: (2,-2) (one unit above the vertex on the axis of symmetry)
\n" ); document.write( "..
\n" ); document.write( "Vertex and Directrix:
\n" ); document.write( " -1/8(y+3)^2=(x-1)
\n" ); document.write( " -(y+3)^2=8(x-1)
\n" ); document.write( "This is a parabola with axis of symmetry: y=-3 of the standard form: (y-k)^2=4p(x-h), with (h,k) being the (x,y) coordinates of the vertex. Parabola opens leftward.
\n" ); document.write( "For given equation:-(y+3)^2=8(x-1)
\n" ); document.write( "vertex:(1,-3)
\n" ); document.write( "4p=8
\n" ); document.write( "p=4
\n" ); document.write( "Directrix: x=5 (a line 4 units to the right of the vertex and perpendicular to the axis of symmetry, y=-3) \n" ); document.write( "