document.write( "Question 49170: How would you factor these four problems:\r
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document.write( "1) x2- 64
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document.write( "2)x4-y4
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document.write( "3)x2-7X+10
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document.write( "4)2X2- 5x-3 \n" );
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Algebra.Com's Answer #32593 by Nate(3500) ![]() You can put this solution on YOUR website! 1) x^2 - 64 find factors of -64 that sum to 0 : -8 and 8 \n" ); document.write( "x^2 - 8x + 8x - 64 \n" ); document.write( "(x^2 - 8x) + (8x - 64) \n" ); document.write( "x(x - 8) + 8(x - 8) \n" ); document.write( "(x + 8)(x - 8) \n" ); document.write( "2) x^4 - y^4 \n" ); document.write( "Just as you see above: (a - b)(a + b) = a^2 - b^2 \n" ); document.write( "what are 'a' and 'b' for x^4 - y^4 in a^2 - b^2 \n" ); document.write( "a = x^2 and b = y^2 \n" ); document.write( "(x^2 - y^2)(x^2 + y^2) \n" ); document.write( "3)x^2 - 7x + 10 find factors of 10 that sum to -7: -5 and -2 \n" ); document.write( "x^2 - 5x - 2x + 10 \n" ); document.write( "(x^2 - 5x) + (-2x + 10) \n" ); document.write( "x(x - 5) - 2(x - 5) \n" ); document.write( "(x - 2)(x - 5) \n" ); document.write( "4) 2x^2 - 5x - 3 find factors of -6 that sum to -5: -6 and 1 \n" ); document.write( "2x^2 - 6x + x - 3 \n" ); document.write( "(2x^2 - 6x) + (x - 3) \n" ); document.write( "2x(x - 3) + 1(x - 3) \n" ); document.write( "(2x + 1)(x - 3) \n" ); document.write( " |