document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=475219>Question 475219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the average score of all golfers for a particular course has a mean of 80 and a standard deviation of 5. suppose 100 golfers played the course today. find the probability that the average score of the 100 golfers exceeds 81 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325844 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the average score of all golfers for a particular course has a mean of 80 and a standard deviation of 5. suppose 100 golfers played the course today. find the probability that the average score of the 100 golfers exceeds 81<BR>\n" );
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document.write( "t(81) = (81-80)/[5/sqrt(100)] = 1/(1/2)= 2<BR>\n" );
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document.write( "P(x > 81) = P(t > 2 when df = 99) = 0.0241<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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