document.write( "Question 475188: PLEASE solve these problems PLEASE !!\r
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document.write( "log(3)5+log(3)x=log(3)10
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document.write( "log(1/7)x=-1
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document.write( "2ln3x+1=5
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document.write( "log(3)0.1+2log(3)x=log(3)2+log(3)5
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document.write( "log(b)9=2
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document.write( "1/4log(2)16+1/2log(2)49=log(2)2x
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document.write( "3^2m=16^-1
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document.write( "4^ex-5=1\r
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document.write( "THESE ARE THE ANSWER CHOICES :
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document.write( "2 , 5 , 14 , -2 , 3.2147 , 10 , 7 , 1.0986 , 0.5537 , 4 , 2.4630 , 3 \n" );
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Algebra.Com's Answer #325838 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! log(3)5+log(3)x=log(3)10 \n" ); document.write( " \n" ); document.write( "Adding logs --> multiply \n" ); document.write( " \n" ); document.write( "5x = 10 \n" ); document.write( "x = 2 \n" ); document.write( "----------------- \n" ); document.write( "log(1/7)x=-1 \n" ); document.write( "Is that log of (x/7) ? or log or x*log(1/7) ? \n" ); document.write( "------------------- \n" ); document.write( "2ln3x+1=5 \n" ); document.write( "2ln(3x) = 4 \n" ); document.write( "ln(3x) = 2 \n" ); document.write( "3x = e^2 \n" ); document.write( "x = e^2/3 \n" ); document.write( "---------- \n" ); document.write( "log(3)0.1+2log(3)x=log(3)2+log(3)5 \n" ); document.write( "Similar to the 1st one. \n" ); document.write( "-------------- \n" ); document.write( "log(b)9=2 \n" ); document.write( "b^2 = 9 \n" ); document.write( "b = 3 \n" ); document.write( "--------------- \n" ); document.write( "1/4log(2)16+1/2log(2)49=log(2)2x \n" ); document.write( "Similar to the 1st one. \n" ); document.write( "---------------------- \n" ); document.write( "3^2m=16^-1 \n" ); document.write( "Is 2 the exponent? or 2m? \n" ); document.write( "---------------- \n" ); document.write( "4^ex-5=1 \n" ); document.write( "4^ex = 6x \n" ); document.write( "ex = 6^(1/4) \n" ); document.write( "x = 6^(1/4)/e \n" ); document.write( " \n" ); document.write( " |