document.write( "Question 475083: I am a little confused on this problem and not sure where to start. Help would be greatly apprieciated.\r
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document.write( "The polynomial 0.0014x^3-0.07x^2+1.5x+11 models natural gas consumption in trillions of cubic feet, where x=0 corresponds to 1960, x=1 to 1961, and so on. In which year between 1979 and 1990 was natural gas consumption about 21.7 trillion cubic feet? \r
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document.write( "Thanks Abby \n" );
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Algebra.Com's Answer #325776 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! I'm not sure I understand this either. \n" ); document.write( ": \n" ); document.write( "The polynomial 0.0014x^3-0.07x^2+1.5x+11 models natural gas consumption in trillions of cubic feet, \n" ); document.write( " where x=0 corresponds to 1960, x=1 to 1961, and so on. \n" ); document.write( " In which year between 1979 and 1990 was natural gas consumption about 21.7 trillion cubic feet? \n" ); document.write( ": \n" ); document.write( "Write the given equation to equal 21.7 \n" ); document.write( ".0014x^3 - .07x^2 + 1.5x + 11 = 21.7 \n" ); document.write( "subtract 21.7 from both sides \n" ); document.write( ".0014x^3 - .07x^2 + 1.5x + 11 - 21.7 = 0 \n" ); document.write( ": \n" ); document.write( ".0014x^3 - .07x^2 + 1.5x - 10.7 = 0 \n" ); document.write( ": \n" ); document.write( "Plot the equation: \n" ); document.write( " \n" ); document.write( "You can see x ~ 13 yrs which would be 1973, This amt will not occur between 1979 and 1990 \n" ); document.write( " \n" ); document.write( " |