document.write( "Question 475032: John had a square patio. After expanding the length by 20 ft. and the width by 10 ft. the area was 999 ft^2 What was the perimeter of the original patio? \n" ); document.write( "
Algebra.Com's Answer #325752 by ankor@dixie-net.com(22740)\"\" \"About 
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John had a square patio. After expanding the length by 20 ft. and the width by 10 ft. the area was 999 ft^2
\n" ); document.write( " What was the perimeter of the original patio?
\n" ); document.write( ":
\n" ); document.write( "Let x = the length of one side of the square patio
\n" ); document.write( "then
\n" ); document.write( "(x+20) = the length of the expanded patio
\n" ); document.write( "and
\n" ); document.write( "(x+10) = the width of the expanded patio
\n" ); document.write( ":
\n" ); document.write( "Expanded area
\n" ); document.write( "(x+20)(x+10) = 999
\n" ); document.write( "FOIL
\n" ); document.write( "x^2 + 10x + 20x + 200 = 999
\n" ); document.write( ":
\n" ); document.write( "x^2 + 30x + 200 - 999 = 0
\n" ); document.write( ":
\n" ); document.write( "x^2 + 30x - 799 = 0
\n" ); document.write( "You can solve this using the quadratic formula, but this will factor to:
\n" ); document.write( "(x+47)(x-17) = 0
\n" ); document.write( "the positive solution:
\n" ); document.write( "x = 17 ft
\n" ); document.write( "then
\n" ); document.write( "4(17) = 68 ft is the original perimeter of the patio
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the area of the expanded patio
\n" ); document.write( "(17+20)(17+10) =
\n" ); document.write( "37 * 27 = 999 \n" ); document.write( "
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