document.write( "Question 475047: I am reading my solutions and I don't understand how I get from one tableau to another. We pivoted around the second row and second column.
\n" ); document.write( "1 2 4 1 0 0 | 8
\n" ); document.write( "3 8 1 0 1 0 | 10
\n" ); document.write( "-4 -32 1 0 0 1 | 0\r
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\n" ); document.write( "\n" ); document.write( "1 0 15 4 -1 0 | 22
\n" ); document.write( "3 8 1 0 1 0 | 10
\n" ); document.write( "8 0 5 0 4 1 | 40
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Algebra.Com's Answer #325737 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Any row in a matrix, can be replaced by the sum of a constant times any other row plus row i. That is:\r
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\n" ); document.write( "\n" ); document.write( "Actually, in more general terms, you can multiply both rows by constants if it makes sense to do so, thus:\r
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\n" ); document.write( "\n" ); document.write( "1. Multiply Row 2 by 4: 12 32 4 0 4 0 | 40\r
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\n" ); document.write( "\n" ); document.write( "2. Add the result of Step 1 to Row 3:\r
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\n" ); document.write( "\n" ); document.write( "12 + (-4) = 8\r
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\n" ); document.write( "\n" ); document.write( "32 + (-32) = 0\r
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\n" ); document.write( "\n" ); document.write( "4 + 1 = 5\r
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\n" ); document.write( "\n" ); document.write( "0 + 0 = 0\r
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\n" ); document.write( "\n" ); document.write( "4 + 0 = 4\r
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\n" ); document.write( "\n" ); document.write( "0 + 1 = 1\r
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\n" ); document.write( "\n" ); document.write( "40 + 0 = 40\r
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\n" ); document.write( "\n" ); document.write( "Hence: 8 0 5 0 0 4 1 | 40\r
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\n" ); document.write( "\n" ); document.write( "3. Replace Row 3 with the results of Step 2.\r
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\n" ); document.write( "\n" ); document.write( "Note: Just because you multiplied Row 2 by 4 in order to drive the 3rd Row 2nd Column element to zero, doesn't mean you have to replace Row 2 with the results of the multiplication.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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\"The

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