document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=474991>Question 474991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am a number less than 100 but greater than 75. My tens digit is thrice my ones digit. What number am I? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325714 by </B><A HREF=/tutors/aboutme.mpl?userid=karaoz><B>karaoz(32)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=karaoz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=karaoz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Since I must be greater than 75 and less than 100, I can only be a two digit number whose first digit is one of these 3 digits: 7, 8 and 9.<BR>\n" );
document.write( "Since my first digit is three times my second digit, this means that my first digit is divisible by 3,<BR>\n" );
document.write( "The only one divisible by 3 is 9. (neither 7 nor 8 are divisible by 9). <BR>\n" );
document.write( "So, my first digit is 9.<BR>\n" );
document.write( "And again, because my first digit is three times my second digits, this means that my second digit is 3.<br><BR>\n" );
document.write( "I am 93! Yes! Yes! Yes... I finally know myself!<br><BR>\n" );
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