document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=474984>Question 474984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of an angle is twice the measure of its supplementary angle.find its measure </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325708 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325708\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the measure of an angle is twice the measure of its supplementary angle.find its measure<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "x + y = 180 degrees<BR>\n" );
document.write( "x = 2y<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Substitute and solve for \"y\":<BR>\n" );
document.write( "2y+y = 180<BR>\n" );
document.write( "y = 60 degrees<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = 2y = 120 degrees<BR>\n" );
document.write( "=============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );