document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=474953>Question 474953</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need your help\r<BR>\n" );
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document.write( "Solution A is 30% acid and solution B is 60% acid. How many gallons of each solution must be used to create a 60 gallons miture that is 50% acid?\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325696 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution A is 30% acid and solution B is 60% acid. How many gallons of each solution must be used to create a 60 gallons miture that is 50% acid?<BR>\n" );
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document.write( "Let x = amount (gal) of 30%<BR>\n" );
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document.write( "60-x = amount of 60%<BR>\n" );
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document.write( ".30x + .60(60-x) = .50(60)<BR>\n" );
document.write( ".30x + 36-.60x = 30<BR>\n" );
document.write( "36-.30x = 30<BR>\n" );
document.write( "-.30x = -6<BR>\n" );
document.write( "x = 20 gals of 30% acid<BR>\n" );
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document.write( "60% acid:<BR>\n" );
document.write( "60-x = 60-20 = 40 gals<BR>\n" );
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