document.write( "Question 474935: Please help me solve this word problem on age: Six years ago, Wendy was twice the age of Thao. At present, Wendy is 30 years older than Thao. Find the present age of each woman. \n" ); document.write( "
Algebra.Com's Answer #325681 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Thao = x years now \n" ); document.write( "Wendy = x+30\r \n" ); document.write( "\n" ); document.write( "6 years ago \n" ); document.write( "Thao = x-6 \n" ); document.write( "Wendy = (x+30)-6==>x+24\r \n" ); document.write( "\n" ); document.write( "x+24=2(x-6) \n" ); document.write( "x+24=2x-12 \n" ); document.write( "2x-x=24+12 \n" ); document.write( "x=36 years Thao's age now \n" ); document.write( "36+30 = 66 years Wendy's age\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |