document.write( "Question 49117This question is from textbook Beginning Algebra
\n" ); document.write( ": You have at least $30 in change in your drawer, consisting of dimes and quarters. Write an inquality that shows the different number of coins in your drawer.\r
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Algebra.Com's Answer #32565 by AnlytcPhil(1807)\"\" \"About 
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You have at least $30 in change in your drawer, consisting of dimes and\r\n" );
document.write( "quarters. Write an inquality that shows the different number of coins in\r\n" );
document.write( "your drawer. How do I do this?\r\n" );
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document.write( "Suppose you have X dimes.  Then they are worth $.10X\r\n" );
document.write( "Suppose you have Y quarters.  Then they are worth $.25Y\r\n" );
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document.write( "Together they are worth $.10X + $.25Y\r\n" );
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document.write( "Since you have at least $30, what they are worth together must either \r\n" );
document.write( "be equal to $30 or greater than $30, so\r\n" );
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document.write( "$.10X + $.25Y > $30\r\n" );
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document.write( "You can drop the dollar signs\r\n" );
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document.write( ".10X + .25Y > 30\r\n" );
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document.write( "If you like, you can multiply thru by 100 to remove the decimals\r\n" );
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document.write( "10X + 25Y > 3000\r\n" );
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document.write( "then you can divide thru by 5\r\n" );
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document.write( "2X + 5Y > 600\r\n" );
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document.write( "However, probably\r\n" );
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document.write( ".10X + .25Y > 30\r\n" );
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document.write( "will be sufficient.\r\n" );
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document.write( "Edwin
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