document.write( "Question 474837: After j candies were given to k kids, each kid has the same number of candies, with four candies remaining. In terms of j and k, how many candies did each kid get?\r
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document.write( "A) (j/k) + 4
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document.write( "B) (j/k) - 4
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document.write( "C) (j + 4)/k
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document.write( "D) (j - 4)/k
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document.write( "E) (jk)/k + 4\r
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document.write( "Please explain how I could approach and solve this problem, thanks! \n" );
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Algebra.Com's Answer #325617 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! There were j candies, but j-4 were actually given (since there was a remainder of 4). This was distributed over k kids, so each kid got (j-4)/k candies. \n" ); document.write( " |