document.write( "Question 49132: Hi, I have a question and it is find the slope of the linear function
\n" ); document.write( "f(t)=(3-4t)/5.\r
\n" ); document.write( "\n" ); document.write( "I'm not sure, but this is what I came up with:
\n" ); document.write( "f(t)=(3-4t)/5
\n" ); document.write( "5=3-4t
\n" ); document.write( "f(t)= -4t-2
\n" ); document.write( "Therefore since it's in form of y=mx+c the slope is m, which is -4
\n" ); document.write( "Am I even on the right track?????
\n" ); document.write( "Thanks, Christa.
\n" ); document.write( "

Algebra.Com's Answer #32559 by venugopalramana(3286)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Hi, I have a question and it is find the slope of the linear function
\n" ); document.write( "f(t)=(3-4t)/5.
\n" ); document.write( "I'm not sure, but this is what I came up with:
\n" ); document.write( "f(t)=(3-4t)/5.....OK
\n" ); document.write( "5=3-4t....NO YOU FORGOT TO TAKE F(T) ON LHS..IT IS
\n" ); document.write( "5F(T)=3-4T.....BUT THIS IS NOT THE WAY...HAVE A CLEAR OBJECTIVE IN VIEW..
\n" ); document.write( "STD.EQN.IS Y=MX+C...WHERE SLOPE=M AND Y INTERCEPT=C
\n" ); document.write( "SO.....CALL F(T)=Y
\n" ); document.write( "Y=(3-4T)/5=15-4T/5
\n" ); document.write( "HENCE M= SLOPE=-4/5
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