document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=474798>Question 474798</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Wallace and Vernonville are 208 miles apart. A car leaves Wallace travailing towards Vernonville, and another car leaves Vernonville at the same time, traviling towards Wallace. The car leaving Wallace avarages 10 miles per hour more than the other, and they meet after 1 hour and 36 minutes. What are the avetage speeds of the cars?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325589 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> car leaving wallace x mph<BR>\n" );
document.write( "Car leaving Vernonville = x-10 mph\r<BR>\n" );
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document.write( "Towards each other so speed = x+x-10==>2x-10\r<BR>\n" );
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document.write( "D= 208<BR>\n" );
document.write( "t=1h 36 m ===> 8/5 hours<BR>\n" );
document.write( "speed = 2x-10\r<BR>\n" );
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document.write( "speed = d/t\r<BR>\n" );
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document.write( "speed = 208/(8/5)<BR>\n" );
document.write( "2x-10 = 208*5/8<BR>\n" );
document.write( "2x-10 =26*5<BR>\n" );
document.write( "2x-10=180<BR>\n" );
document.write( "2x=180+10<BR>\n" );
document.write( "2x=190<BR>\n" );
document.write( "x=95 speed of one car<BR>\n" );
document.write( "other car speed = 85 mph </SPAN>\n" );
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