document.write( "Question 474696: 6.02x10^-4=0.153^-N
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Algebra.Com's Answer #325544 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
You would use logarithms:
\n" ); document.write( "\"6.02X10%5E%28-4%29+=+0.153%5E%28-N%29\" Take the log (common) of both sides.
\n" ); document.write( "\"Log%5B10%5D%286.02X10%5E%28-4%29%29+=+Log%5B10%5D%280.153%5E%28-N%29%29\" Apply the \"power rule\" to the right side.
\n" ); document.write( "\"Log%5B10%5D%286.02X10%5E%28-4%29%29+=+-N%2ALog%5B10%5D%280.153%29\" Divide both sides by \"Log%5B10%5D%280.153%29\"
\n" ); document.write( "\"-N+=+%28Log%286.02X10%5E%28-4%29%29%29%2F%28Log%280.153%29%29\" Evaluate using your calculator.
\n" ); document.write( "\"-N+=+3.9429\" so...
\n" ); document.write( "\"N+=+-3.943\" Rounded.
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