document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=474599>Question 474599</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three less than twice the third of three consecutive integers equals the sum of the three integers. Find the integers. \r<BR>\n" );
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document.write( "I have this so far:<BR>\n" );
document.write( "2(abc/3)-3 = a+b+c\r<BR>\n" );
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document.write( "a=integer #1, b=integer # 2, and c=integer # 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325483 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Instead of letting the integers being a,b,c (this makes for a three-variable equation which might not be solvable) we take advantage that the integers are consecutive, so we let the integers be a, a+1, and a+2. Then,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE 2(a+2) - 3 = a + (a+1) + (a+2)\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE 2a + 1 = 3a + 3\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE a = -2\">\r<BR>\n" );
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document.write( "Integers are -2, -1, 0. </SPAN>\n" );
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