document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=474463>Question 474463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The vertices R, S, T of the right triangle RST are the centers of 3 circles. The circles with centers R and T are externally tangent to the circle with center S. Find the perimeter, in cm, of triangle RST.\r<BR>\n" );
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document.write( "Circle with center       Diameter<BR>\n" );
document.write( "     R                       6<BR>\n" );
document.write( "     S                       18<BR>\n" );
document.write( "     T                       14  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325402 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diameter of R is equal to 6 so the radius of R is equal to 3.<BR>\n" );
document.write( "The diameter of S is equal to 18 so the radius of S is equal to 9.<BR>\n" );
document.write( "The diameter of T is equal to 14 so the radius of T is equal to 7.<BR>\n" );
document.write( "The picture below shows what is happening.<BR>\n" );
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document.write( "Radius of circle R is 3.<BR>\n" );
document.write( "Radius of circle S is 9.<BR>\n" );
document.write( "Radius of circle T is 7.<BR>\n" );
document.write( "RS is equal to 12 which is the radius of circle R plus the radius of circle S.<BR>\n" );
document.write( "ST is equal to 16 which is the radius of circle S plus the radius of circle T.<BR>\n" );
document.write( "RT is the hypotenuse of triangle RST which can be found using the formula:<BR>\n" );
document.write( "RT squared = RS squared plus ST squared.<BR>\n" );
document.write( "This makes RT squared equal to 12 squared plus 16 squared which is equal to 400.<BR>\n" );
document.write( "this makes RT equal to the square root of 400 which is equal to 20.<BR>\n" );
document.write( "The dimensions of triangle RST are:<BR>\n" );
document.write( "RS = 12<BR>\n" );
document.write( "ST = 16<BR>\n" );
document.write( "RT = 20<BR>\n" );
document.write( "The perimeter of triangle RST is therefore equal to 48.\r<BR>\n" );
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