document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=474448>Question 474448</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Each interior angle of a regular polygon is 20 more than 3 times the measure of each exterior angle. Find the number of sides of each polygon. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325400 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Each interior angle of a regular polygon is 20 more than 3 times the measure of each exterior angle. Find the number of sides of each polygon.<BR>\n" );
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document.write( "Each interior/exterior pair is supplementary.<BR>\n" );
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document.write( "Exterior angle: x<BR>\n" );
document.write( "Interior angle: 3x+20<BR>\n" );
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document.write( "x + 3x + 20 = 180<BR>\n" );
document.write( "4x = 160<BR>\n" );
document.write( "x = 40<BR>\n" );
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document.write( "The sum of all the exterior angles is 360 degrees.<BR>\n" );
document.write( "# of exterior angles = 360/40 = 9<BR>\n" );
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document.write( "# of sides = # of exterior angles = 9<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
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