document.write( "Question 49090: May you please help me with this: y=3x+2
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Algebra.Com's Answer #32539 by AnlytcPhil(1806)\"\" \"About 
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y = 3x + 2\r\n" );
document.write( "2y - 14 = - 4x\r\n" );
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document.write( "Since the first equation is solved for y, and since y is equal\r\n" );
document.write( "to 3x + 2, we put that in parentheses like this (3x + 2), then\r\n" );
document.write( "we take the other equation and instead of y put what y equals,\r\n" );
document.write( "namely (3x + 2).  Then solve for x\r\n" );
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document.write( "         2y - 14 = -4x\r\n" );
document.write( "  2(3x + 2) - 14 = -4x\r\n" );
document.write( "     6x + 4 - 14 = -4x \r\n" );
document.write( "         6x - 10 = -4x \r\n" );
document.write( "         6x + 4x = 10\r\n" );
document.write( "             10x = 10\r\n" );
document.write( "               x = 1 \r\n" );
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document.write( "Now take the first equation\r\n" );
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document.write( "               y = 3x + 2\r\n" );
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document.write( "and substitute (1) for x\r\n" );
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document.write( "               y = 3(1) + 2\r\n" );
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document.write( "then finish the right side\r\n" );
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document.write( "               y = 3 + 2\r\n" );
document.write( "               y = 5\r\n" );
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document.write( "So the solution is (x,y) = (1,5)\r\n" );
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document.write( "Edwin

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