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volume of the water on the roof is equal to h1 * a1 where h1 is the height of the volume of water on the roof and a1 is the area of the base of the roof.
\n" ); document.write( "volume of the water in the tank is equal to h2 * a2 where h2 is the height of the volume of water in the tank and a2 is the area of the base of the tank.
\n" ); document.write( "the area of the base of the roof is equal to 12 * 44 = 528 square meters.
\n" ); document.write( "the area of the base of the tank is equal to pi*r^2 which is equal to pi*2^2 which is equal to 4*pi.
\n" ); document.write( "the volume of water on the roof is therefore equal to .005 * 528 = 2.64 cubic meters.
\n" ); document.write( "the volume of water in the tank is therefore equal to h2 * 4 * pi.
\n" ); document.write( "since the volume in the tank and the volume on the roof is the same, then these equations can be made equal to each other so you get:
\n" ); document.write( "2.64 cubic inches = h2 * 4 * pi.
\n" ); document.write( "divide both sides of this equation by 4 * pi and you get:
\n" ); document.write( "2.64 / (4 * pi) = h2
\n" ); document.write( "solve for h2 and you get:
\n" ); document.write( "h2 = .210084525 meters.
\n" ); document.write( "h1 was given in millimeters which we converted to meters by dividing by 1000 to get .005 meters.
\n" ); document.write( "h2 is given in mters which we can convert to millimeters by multiplying by 1000 to get 210.084525 millimeters.
\n" ); document.write( "the general formula used to solve this problem would be:
\n" ); document.write( "h1 * 528 = h2 * 4 * pi
\n" ); document.write( "if we know h1 (height of the water on the roof), then we can solve for h2.
\n" ); document.write( "if we know h2 (height of the water in the tank), then we can solve for h1.
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