document.write( "Question 470432: Solve the logarithmic equation using the one-to-one property.\r
\n" ); document.write( "\n" ); document.write( "log (x + 5) = log (5x - 4)
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Algebra.Com's Answer #325379 by lwsshak3(11628)\"\" \"About 
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Solve the logarithmic equation using the one-to-one property.
\n" ); document.write( "log (x + 5) = log (5x - 4)
\n" ); document.write( "**
\n" ); document.write( "log (x+5)- log (5x-4)=0
\n" ); document.write( "log[(x+5)/(5x-4)]=0
\n" ); document.write( "convert to exponential form: (base (10) raised to log of number(0)=number(x+5)/(5x-4)
\n" ); document.write( "10^0=(x+5)/(5x-4)=1
\n" ); document.write( "x+5=5x-4
\n" ); document.write( "4x=9
\n" ); document.write( "x=9/4
\n" ); document.write( "Check:
\n" ); document.write( "log(9/4+5)-log(5*9/4-4)
\n" ); document.write( ".8603-.8603=0
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