document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=471049>Question 471049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5. Change the logarithmic expression to an equivalent expression involving an exponent.<BR>\n" );
document.write( " log[2](1/32)=k\r<BR>\n" );
document.write( "\n" );
document.write( "can someone help me out? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325375 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325375\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5. Change the logarithmic expression to an equivalent expression involving an exponent.<BR>\n" );
document.write( "log[2](1/32)=k <BR>\n" );
document.write( "**<BR>\n" );
document.write( "log[2](1/32)=k<BR>\n" );
document.write( "log2(1/2^5)=k<BR>\n" );
document.write( "log2(2^-5)=k<BR>\n" );
document.write( "convert to exponential form:(base(2) raised to log of number(k)=number(2^-5)<BR>\n" );
document.write( "2^k=2^-5<BR>\n" );
document.write( "k=-5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );